Question 865839
<pre>
{{{ log( 2, 1 ) }}} - {{{ log( 4, x ) }}} + {{{ log( 4, y ) }}} = 2

Please solve for x
Please show all steps   
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While the answer is correct, the steps the other person showed are WAY TOO UNNECESSARY. For example, why did he convert from base 4 to
base 2? To this author, it's a little lengthy, and quite time-consuming. A lot less steps can be used to reach the same goal: the correct answer!

{{{log (2, (1)) - log (4, (x)) + log (4, (y)) = 2}}}
           {{{0 - log (4, (x)) + log (4, (y)) = 2}}}
        {{{log (4, (x)^(- 1)) + log (4, (y)) = 2}}} ----- Applying {{{a*log (b, (c)) = log (b, (c^a))}}}
              {{{log (4, (1/x)) + log (4, (y)) = 2}}}
                          {{{log (4, (1/x)y) = 2}}} ----- Applying {{{log (b, (c)) + log (b, d))}}} = {{{log (4, (c*d))}}}
                                      {{{(y/x) = 4^2}}} ---- Converting to EXPONENTIAL form
                                      {{{(y/x) = 16}}}
                                       16x = y ----- Cross-multiplying
                                          {{{highlight(x = y/16)}}}</font></font></font></b></pre>