Question 883161
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log2(x - 6) + log2(x - 4) = log2 x solve the logarithmic equation. and round. 
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x = 3 or x = 8, as stated by the other person, is partly WRONG!   

{{{log (2, (x - 6)) + log (2, (x - 4)) = log (2, (x))}}}
Looking at the logarithmic equation, the smallest log argument, x - 6 MUST be > 0.
So, x - 6 > 0, and therefore, x > 6. 

We then have: {{{log (2, (x - 6)) + log (2, (x - 4)) = log (2, (x))}}}, with x > 6

The x-value 3 is NOT > 6, which makes it EXTRANEOUS and an INVALID/UNACCEPTABLE solution. On the
other hand, the x-value 8 is > 6, which makes it the ONLY solution to this equation.</font></font></font></b></pre>