Question 276444
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Factor by grouping x^2-y^2-ax-ay
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        In the post by @mananth, factoring is made incorrectly, giving wrong answer.

        I came to bring a correct solution.



<pre>
   x^2-y^2-ax-ay = 

= (x+y)*(x-y) - a(x+y)

= (x+y)*{x-y-a)


This is the final <U>ANSWER</U>:  x^2-y^2-ax-ay = (x+y)*(x-y-a).
</pre>

Solved correctly.