Question 275504
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if you take a certain two-digit number and reverse its digits to get another two-digit number, 
then add these two numbers together, their sum is 132. what is the original number?
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Let the digit in the units place be y
& in the tens place be x
So the number will be 10x+y
On reversing the digits
the number becomes 10y+x
The sum of the two = 132
10x+y + 10y+x= 132
11x+11y=132


x+y=12


From this equation, SEVEN different two-digit integer numbers are possible
93, 84, 75, 66, 57, 48, 39.


All the SEVEN numbers when reversed and added give you 132.