Question 275984
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a cyclist travels 30mi in 3 hours going against the wind and 80mi in 5 hours with wind. 
What is the rate of the cyclist in still air and what is the rate of the wind?
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The solution in the post by @mananth is incorrect and makes no sense.


The fact that the rate of the cyclist is  'x'  miles per hour at no wind and the fact 
that the rate of the wind is  'y'  miles per hour DO NOT IMPLY that the effective rate
of the cyclist with the wind is (x+y) mph and the effective rate of the cyclist against
the wind is (x-y) miles per hour.


Only a person absolutely illiterate in Physics could create/compose such a nonsense.


No one peer-reviewed Math textbook or Physics textbook would publish such a non-sensical
gibberish.


My advise to a reader is to ignore the problem itself as a kind of nonsense
and ignore the solution by @mananth since it is WRONG TEACHING.



The creator of this "problem" should be ashamed of himself for composing such nonsense 
and distributing it on the Internet.