Question 264812
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what are the factors of 6r^2+3rs-18s^2 ?
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        The solution in the post by @mananth is incorrect - simply ignore it.

        See below my correct solution.



<pre>
    6r^2 + 3rs - 18s^2 = 

    = 3*(2r^2 + rs - 6s^2) =

    = 3*(2r^2 + 4rs - 3rs - 6s^2) =

    = 3*(2r(r+2s) - 3s(r+2s)) =

    = 3*(2r-3s)(r+2s).    <U>ANSWER</U>
</pre>

Solved correctly.