Question 265347
These consecutive odd integers may be x, x+2, x+4.

Guessing that the "sum of the second and third" was really meant, then
{{{x^2=6(x+2+x+4)+9}}}
{{{x^2=6(2x+6)+9}}}
{{{x^2=12x+36+9}}}
{{{x^2=12x+45}}}
{{{x^2-12x=45}}}
{{{x(x-12)=45}}}
{{{x(x-12)=15*3=45}}}
This means the first integer would be 15.


The way the given problem was described cannot be correct.