Question 265347
Consecutive odd integers
 n, n+2, n+4


The description
{{{(n)^2=9+6(n+(n+2))}}}


Steps to solve
{{{n^2=9+6(2n+2)}}}
{{{n^2=9+12n+12}}}
{{{n^2-12n=21}}}
{{{n(n-12)=21}}}, not seeing anything with this.

{{{n^2-12n-21=0}}}
{{{discriminant}}}  {{{(12)^2-4*(-21)=144+84=228}}}
and {{{sqrt(228)=15.0997}}}

 
The exercise problem is broken.  No solution.