Question 264398
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Two hikers started from opposite ends of a 29-mile trail. One hiker walked 1.25 mph slower than the other hiker, 
and they met after 4 hours. How fast did each hiker walk?
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        The solution and the answer in the post by @mananth both are incorrect.

        The fact that his answer values are incorrect, everybody can check manually.


        Below is my correct solution.



Let x be the rate of the slower hiker, in miles per hour.
Then the rate of the faster hiker is (x+1.25) miles per hour.


Write the total distance equation


            4x + 4*(x+1.25) = 29 miles.


Simplify and find x


            4x + 4x + 4*1.25 = 29,

               8x   +    5   = 29,    --->    8x = 29 - 5 = 24,    --->   x = 24/8 = 3.


<U>ANSWER</U>.  &nbsp;&nbsp;The slower hiker rate is 3 mph;  &nbsp;&nbsp;the faster hiker rate is 3+1.25 = 4.25 mph.


<U>CHECK</U>.  &nbsp;&nbsp;&nbsp;&nbsp;4*(3 + 4.25) = 4*7.25 = 29 miles,  &nbsp;the total distance.   &nbsp;&nbsp;&nbsp;&nbsp;! correct !
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Solved correctly.