Question 262142
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Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour 
and train B is traveling at 60 miles per hour. Train A passes a station at 5:25 A.M. If train B passes the same 
station at 5:37 A.M, at what time will train B catch up to train A?
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        The solution in the post by @mananth is incorrect due to his errors in reasoning and in calculations.

        I came to bring a correct solution.



<pre>
At 5:37 AM,  train A is  40 mph x 12 minutes = 40 mph x 0.2 of an hour = 8 miles ahead train B,
and the rate of approaching train B to train A is  60-40 = 20 mph.


So, train B will catch train A in  {{{8/20}}} = {{{24/60}}} = 24 minutes.


So, the catching time is 5:37 AM plus 24 minutes, which is  6:01 AM.


<U>ANSWER</U>.  The catching time is  6:01 AM.
</pre>

Solved correctly.