Question 1113133
<pre>
Show that log base a (a^2 - x^2) = 2 + log base a (1 - x^2/a^2)
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{{{log (a, (a^2 - x^2)) = 2 + log (a, (1 - x^2/a^2))}}}
Let's focus on the R.H.S
{{{log (a, (a^2 - x^2)) = log (a, (a^2)) + log (a, (1 - x^2/a^2))}}} ---- Converting 2 to {{{log (a, (a^2))}}}
{{{log (a, (a^2 - x^2)) = log (a, a^2(1 - x^2/a^2))}}} --- Applying {{{log (b, (c)) + log (b, ((d)))}}} = {{{log (b, (c*d))}}}
{{{log (a, (a^2 - x^2)) = log (a, (a^2 - x^2))}}} ---- Distributing on R.H.S.
              L.H.S. = R.H.S. </font></font></fon></b></pre>