Question 988996
<pre>
&#8730;(7-4&#8730;3) + &#8730;(7+4&#8730;3)
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                         {{{sqrt(7 - 4sqrt(3)) + sqrt(7 + 4sqrt(3))}}}
                 {{{sqrt(7 - 2(2)sqrt(3)) + sqrt(7 + 2(2)sqrt(3))}}}
                     {{{sqrt(7 - 2sqrt(4)sqrt(3)) + sqrt(7 + 2sqrt(4)sqrt(3))}}}
                {{{sqrt(4 + 3 - 2sqrt(4)sqrt(3)) + sqrt(4 + 3 + 2sqrt(4)sqrt(3))}}} ----- Changing 7 to 4 + 3                 
{{{sqrt((sqrt(4))^2 + (sqrt(3))^2 - 2sqrt(4)sqrt(3))}}} + {{{sqrt((sqrt(4))^2 + (sqrt(3))^2 + 2sqrt(4)sqrt(3))}}} ------ Converting {{{system(matrix(2,3, 4, to, (sqrt(4))^2, 3, to, (sqrt(3))^2))}}}
The above is in the form:
                          {{{(a - b)^2}}}  + {{{(a + b)^2}}}, with {{{system(matrix(2,3, a, being, sqrt(4), b, being, sqrt(3)))}}}, and so:
{{{sqrt((sqrt(4))^2 + (sqrt(3))^2 - 2sqrt(4)sqrt(3))}}} + {{{sqrt((sqrt(4))^2 + (sqrt(3))^2 + 2sqrt(4)sqrt(3))}}} then becomes:
                   {{{sqrt((sqrt(4) - sqrt(3))^2)}}} +  {{{sqrt((sqrt(4) + sqrt(3))^2)}}}
                         {{{sqrt(4) - sqrt(3)}}}    +    {{{sqrt(4) + sqrt(3)}}} ----- Cancelling SQUARE and SQUARE ROOT
                               {{{2 - sqrt(3) + 2 + sqrt(3) = highlight(4))}}}</font></font></font></b></pre>