Question 969387
<pre>
sir what is the root of 5+2*root 6
**********************************<font face = tahoma><font size = 2><font color = blue><b>root of 5 + 2*root 6
I take it, this is: {{{sqrt(5 + 2sqrt(6))}}}, the square root of a SURD! If so,
                    {{{sqrt(3 + 2 + 2sqrt(3*2))}}} ----- Changing 5 to 3 + 2, and 6 (in {{{sqrt(6)}}}) to 3*2
                    {{{sqrt(3 + 2 + 2sqrt(3)sqrt(2))}}} ------ Applying {{{sqrt(m*n) = sqrt(m)sqrt(n)}}}
  {{{sqrt((sqrt(3))^2 + (sqrt(2))^2 + 2sqrt(3)sqrt(2))}}} ------ Converting {{{system(matrix(2,3, 3, to, (sqrt(3))^2, 2, to, (sqrt(2))^2))}}}
The above is in the form: {{{(a + b)^2}}}, with {{{system(matrix(2,3, a, being, sqrt(3), b, being, sqrt(2)))}}}, and so:
{{{sqrt((sqrt(3))^2 + (sqrt(2))^2 + 2sqrt(3)sqrt(2))}}} then becomes: {{{sqrt((sqrt(3) + sqrt(2))^2)}}} 
                                                                               {{{highlight(sqrt(3) + sqrt(2))}}} ----- Cancelling SQUARE and SQUARE ROOT</font></font></font></b></pre>