Question 864099
<pre>
Can you show me how to Rationalize the denominator and simply the equation 
6 / the square root of 2 - the square root of 3.
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{{{(highlight(sqrt(6)/(sqrt(2) - sqrt(3))))}}}{{{((sqrt(2) + sqrt(3))/(sqrt(2) + sqrt(3)))}}} = {{{sqrt(6)(sqrt(2) + sqrt(3))/((sqrt(2))^2 - (sqrt(3)))^2}}} = {{{(sqrt(12) + sqrt(18))/(2 - 3)}}} = {{{(2sqrt(3) + 3sqrt(2))/(- 1) = - (2sqrt(3) + 3sqrt(2)) = highlight(- 2sqrt(3) - 3sqrt(2))}}}</font></font></font></b></pre>