Question 1003361
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If 1 is a zero of p(x) =ax^3-(a-1)x-1 then find value of a
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Given that 1 is a 0/1 is a solution, {{{p(x) = ax^3 - (a - 1)x - 1}}} becomes: 
                                                          {{{p(1) = a(1)^3 - (a - 1)1 - 1}}} --- Substituting 1 for x
                                                            0 = a - a + 1 - 1 ------ Substituting 0 for p(1), and simplifying
                                                            0 = 0 (TRUE)

As the above equation proves TRUE, there's NO 1 SPECIFIC value for "a." As such, ANY value of
"a" will SATISFY the function, {{{p(x) = ax^3 - (a - 1)x - 1}}}</font></font></font></b></pre>