Question 459722
<pre>
Simplify each expression by rationalizing the denominator.
3/sqrt(7)
2sqrt(2)/sqrt(5)
3sqrt(2)/sqrt(6)
2sqrt(5)/sqrt(12)
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This problem "asks" to SIMPLIFY by "rationalizing the denominator," NOT providing a calculated value, as the other person did!

      {{{3/sqrt(7) = (3/sqrt(7))(sqrt(7)/sqrt(7)) = highlight(3sqrt(7)/7)}}}, or {{{highlight((3/7)sqrt(7))}}}

{{{2sqrt(2)/sqrt(5) = (2sqrt(2)/sqrt(5))(sqrt(5)/sqrt(5)) = highlight(2sqrt(10)/5)}}}, or {{{highlight((2/5)sqrt(10))}}}

{{{3sqrt(2)/sqrt(6) = (3sqrt(2)/sqrt(6)) * (sqrt(6)/sqrt(6)) = 3sqrt(12)/6 = 3sqrt(4 * 3)/6 = 3sqrt(4)sqrt(3)/6 = 3(2)sqrt(3)/6 = 6sqrt(3)/6 = cross(6)sqrt(3)/cross(6) = highlight(sqrt(3))}}}

{{{2sqrt(5)/sqrt(12) = 2sqrt(5)/2sqrt(3) = cross(2)sqrt(5)/cross(2)sqrt(3) = sqrt(5)/sqrt(3) = (sqrt(5)/sqrt(3))(sqrt(3)/sqrt(3)) = highlight(sqrt(15)/3)}}}, or {{{highlight((1/3)sqrt(15))}}}</pre>