Question 2732
<pre>
I am studing the substitution Method.. and for some reason i can not seem to figure out how to do it.
My teacher has been trying to work with me, but yet when I look at the problem I go blank on what to do. 
I have an equation y = 2x + 7
                   y = 10x - 1   I dont understand how to do this...
********************************************************************
<font face = tahoma><font size = 3><font color = blue><b>
I have no idea why the person who responded did this: y=2x+7
2x=y-7
x=(y-7)/2 ...... [3]

What could possibly make someone solve for "x," and create a 3rd equation, WITH  a FRACTION,
and making things MUCH MORE COMPLEX, when the given equations are: y = 2x + 7
                                                                                                                                y = 10x - 1   
Isn't that the MOST SIMPLEST a system can ever be, READY to be solved using the SUBSTITUTION method? 
y = 2x + 7 ---- eq (i)
y = 10x - 1 --- eq (ii)

The above system MEANS that 2x + 7 = 10x - 1
                                                  2x - 10x = - 1 - 7  
                                                          - 8x = - 8
                                                              x = {{{(- 8)/(- 8) = 1}}}

                                                              y = 2x + 7
                                                              y = 2(1) + 7 ----- Substituting 1 for x in eq (i)
                                                              y = 2 + 7 = 9

                                     Solution set: {{{system(x = 1, y = 9)}}}</pre>