Question 1088632
<pre>
log3 (2x-1) = 2  x =
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log3 (2x-1) = 2  x =
This, most likely is: {{{log (3, (2x - 1)) = 2}}}  x =, instead of {{{log (3, (2x - 1)) = 2x}}} (what the other person surmised!!).
                                           {{{2x - 1 = 3^2}}}
                                         2x - 1 = 9
                                               2x = 9 + 1
                                               2x = 10
                                                 {{{x = 10/2}}} = 5</pre></font></font></b>