Question 822027
<pre>
log3 15 &#8722; log3 40 + log3 648
**********************************
I take it you need this SIMPLIFIED!!<font face = tahoma><font size = 3><b><font color = blue>
{{{log (3, (15)) - log (3, (40)) + log (3, (648)))}}}
{{{log (3, (15/40 * 648))}}} ----- Applying {{{log (b, (c)) - log (b,  (d)) + log (b, (e)))}}} = {{{log (b, (c/d * e))}}} 
{{{log (3, (3cross(15)/8cross(40) * 648))}}} = {{{log (3, (3/8 * 648))}}} = {{{log (3, (3/cross(8) * 81cross(648)))}}} = {{{log (3, (3(81)))}}} = {{{log (3, (3 * 3^4))}}} = {{{log (3, (3^5))}}} = 5</pre>