Question 1026110
<pre>
simplify the expression
log3 (x+1) -log3 (3x^2-3x-6)+log3 (x-2)

The 3 on each log is lowered
****************************
<font face = tahoma><font size = 3><b><font color = blue>
{{{log(3,((x+1)(x-2)/(3x^2-3x-6)))}}} is NOT the simplified form of log3 (x+1) -log3 (3x^2-3x-6)+log3 (x-2), as the
                                other person who responded, indicates!

{{{log (3, (x + 1)) - log (3,  (3x^2 - 3x - 6)) + log (3, (x - 2)))}}}
{{{log (3, ((x + 1)/(3x^2 - 3x - 6) * (x - 2)))}}} ----- Applying {{{log (b, (c)) - log (b,  (d)) + log (b, (e)))}}} = {{{log (b, (c/d * e))}}} 
{{{log (3, ((x + 1)/3(x^2 - x - 2) * (x - 2)))}}} ----- Factoring out GCF, 3, in DENOMINATOR
{{{log (3, ((x + 1)/3(x - 2)(x + 1) * (x - 2)))}}} ---- Factorizing QUADRATIC/TRINOMIAL, in DENOMINATOR
{{{log (3, (cross((x + 1))/3cross((x - 2))cross((x + 1)) * cross((x - 2))))}}} = {{{log (3, (1/3))}}} = {{{log (3, (3^(- 1)))}}} = - 1</pre>