Question 1081944
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80 men can finish the job in 60 days. At the 16th day, 5 men were laid off and at the 45th day, 
10 men were hired. How many days were they delayed finishing the job.
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        I will show you the method, which you (i hope) will remember for all your life.



<pre>
(1)  The entire job is 80 men * 60 days = 4800 man-days.



(2)  80 men worked first 15 day and used 80 * 15 = 1200 man-days.

     The remaining job is 4800 - 1200 = 3600  man days.



(3)  Then (80-5) = 75 men worked from the day 16th till the day 44th inclusively, i.e. 44-15 = 29 days.

     They used 75 * 29 = 2175 man-days, and 3600 - 2175 = 1425 man-days work remained.



(4)  Starting from the 45th day, 75+10 = 85 men work.

     They complete the remaining job in  1425/85 = 16.7647 days, approximately.



(5)  So, the number of days they worked to complete the job is  15 + 29 + 16.7647 = 60.7647.    <U>ANSWER</U>


You can round it in a way you want.
</pre>

Solved and explained.



&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;Counting man-days (or man-hours, or man-minutes) 

&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;is a powerful method solving rate-of-work problems.