Question 890524
<pre>
My question was log of sqrt (x (sqrt (2y (sqrt (z)))) 

What I did was (1/2)logx sqrt (2y (sqrt (z))

(1/2)logx(1/4)logy^2 sqrt (z)

(1/2)logx(1/4)logy^2(1/8)logz

Then factored that to  (1/2)[logx(1/2)logy^2(1/4)logz] 

But my professor counted it as wrong and I hope it's not too confusing the way that I typed it but the formula system wouldn't work for me. I just wanted to see where I went wrong with this question. Thank you! 
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If it's {{{log (sqrt(x*sqrt(2y*sqrt(z))))}}}, then:
{{{log(sqrt(matrix(2,1, " ", x*sqrt(2y*matrix(2,1, " ", z^(1/2))))))}}} ={{{log(sqrt(x*(2y*z^(1/2))^(1/2))))}}} = {{{log(sqrt(matrix(2,1, " ", x* 2^(1/2)y^(1/2)z^(1/4)))))}}}
{{{log((x*2^(1/2)y^(1/2)z^(1/4)))^(1/2)}}} = {{{(1/2)log((x*2^(1/2)y^(1/2)z^(1/4)))}}}, or {{{(1/2)log((2^(1/2)xy^(1/2)z^(1/4)))}}}
OR
{{{log((x^(1/2)*2^((1/2)(1/2))y^((1/2)(1/2))z^((1/4)(1/2))))}}} = {{{log((x^(1/2)*2^(1/4)y^(1/4)z^(1/8)))}}}, or {{{log((2^(1/4)x^(1/2)*y^(1/4)z^(1/8)))}}}</pre>