Question 617405
<pre>
if log base b (2)=x and log base b (3)=y, evaluate the following terms of x and y:

log base b (24)=

log base b (216)=

log base b (16/27)=

(log base b (27))/(log base b (4))=
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{{{log (b, (2)) = x}}}      {{{log (b, (3)) = y}}}

          log base b (24)=             log base b (216)=           log base b (16/27)=   (log base b (27))/(log base b (4))=
{{{system(matrix(6,1,
highlight(log (b, (24))),
log (b, (8*3)),
log (b, (8)) + log (b, (3)),
log (b, (2^3)) + log (b, (3)),
3*log (b, (2)) + log (b, (3)),
highlight(3x + y)))}}} {{{system(matrix(6,1,
highlight(log (b, (216))),
log (b, (8*27)),
log (b, (8)) + log (b, (27)),
log (b, (2^3)) + log (b, (3^3)),
3*log (b, (2)) + 3*log (b, (3)),
highlight(3x + 3y)))}}} {{{system(matrix(5,1,
highlight(log (b, (16/27))),
log (b, (16)) - log (b, (27)),
log (b, (2^4)) - log (b, (3^3)),
4*log (b, (2)) - 3*log (b, (3)),
highlight(4x - 3y)))}}} {{{system(matrix(4,1,
highlight(log (b, (27))/log (b, (4))),
log (b, (3^3))/log (b, (2^2)),
(3*log (b, (3)))/(2*log (b, (2))),
highlight(3y/(2x))))}}}</pre>