Question 174799
<pre>
log(base2)log(base3)log(base4)2^n=2

I don't understand how to solve this.

log(base2)log(base3)log(base4)2^n=2

{{{log (highlight(2), (log (3, (log (4, (2^n)))))) = highlight(2)}}}
        {{{log (3, (log (4, (2^n)))) = highlight(2)^highlight(2)}}}      
       {{{log (highlight(3), (log (4, (2^n)))) = highlight(4)}}}
               {{{log (4, (2^n)) = highlight(3)^highlight(4)}}}
              {{{log (highlight(4), (2^n)) = highlight(81)}}}
                     {{{2^n = 4^81}}}
                     {{{2^n = (2^2)^81}}}
                     {{{2^n = 2^162}}}
                     {{{highlight_green(n) = highlight(highlight_green(162))}}}</pre>