Question 206454
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Here is another path to simplifying this expression using the following property of logarithms:<br>
{{{log(b,(a))=log(b^n,(a^n))}}}<br>
In this problem, {{{4=2^2}}} and {{{9=3^2}}}, so {{{log(4,(9))=log(2,(3))}}}<br>
Then we have<br>
{{{2log(4,(9))-log(2,(3))=2log(2,(3))-log(2,(3))=log(2,(3))}}}<br>
ANSWER: {{{log(2,(3))}}}<br>