Question 206454
<pre>
2 log(base 4) 9 - log(base 2) 3

{{{highlight(2*log (4, (9)) - log (2, (3)))}}}
{{{2*(log (2, (9))/log (2, (4))) - log (2, (3))}}}
{{{2*(log (2, (9))/2) - log (2, (3))}}}
{{{cross(2)*(log (2, (9))/cross(2)) - log (2, (3))}}}
{{{log (2, (9)) - log (2, (3))}}}
{{{log (2, (9/3))}}} = {{{highlight(log (2, (3)))}}}

I think this is what you want: the above log expression to be SIMPLIFIED into a SINGLE log, and not calculated as the other person did!</pre>