Question 1179144
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For what values of c will x^2 +28x + c = 0 have no real solutions? Explain
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The given quadratic equation has no real solutions if and only if its discriminant is a negative value.


The discriminant is  d = 28^2 - 4c = 784 - 4c.


The condition of negativity the discriminant is

    784 - 4c < 0,   or   4c > 784,   c > 784/4 = 196.


<U>ANSWER</U>.  The given equation has no real solutions at c > 196.
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Solved.