Question 96313
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I'm guessing that the "3" and "2" in the statement of the problem are the levels of the roots instead of just coefficients.  So I read the problem as "cube root of 11 times square root of 11".  Then<br>
{{{root(3,11)*root(2,11)=(11)^(1/3)*11^(1/2)=11^(1/3+1/2)=11^(5/6)=root(6,11^5)}}}<br>