Question 1182591
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A 0.5 kg block initially at rest on a frictionless horizontal surface is acted 
upon by a force of 8.0 N for a distance of 4.0 m how much kinetic energy does the block gain
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        The solution by @mananth and his answer both are incorrect.

        I came to bring a correct solution.



Change in Kinetic energy = Work done on object


Work done = F * D = 8.0N  *4 = 32 J


Therefore, block gains 32 Joule of Kinetic energy.


Solved correctly.


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The given mass is irrelevant to the solution.