Question 96205
<br>
...<br>
This is what I have done:
y^4/3 + 3y =0
1. The exp of y is understood to be 1...so does this mean that I need to find the commoon denominator of the exp so that I could add? Should the exp of 3y then be 1/3?
y^4/3 + 3y^1/3= 0<br><br>
No.<br>
As the other tutor says, you seem to be trying to make this problem look like the example in your book, but it is very different.<br>
In the expression "3y" in this problem, the understood exponent "1" is only the exponent of "y" -- it is not the exponent of "3y".<br>
Leave the equation as<br>
y^4/3 + 3y =0<br>
Then, as the other tutor shows, factor out the common factor "y" on the left and solve the problem from there.<br>