Question 975452
<pre>
0= log base 5 (x-2) - log base 5 (2x)

{{{0 = log (5, (x - 2)) - log (5, (2x))}}}
Smaller variable-expression, x - 2 MUST be > 0. We then get: x - 2 > 0___x MUST be > 2. The problem then becomes:
{{{0 = log (5, (x - 2)) - log (5, (2x))}}}, with x > 2.

When solved, we get x = - 2. However, because this x-value is NOT > 2, there are NO SOLUTIONS to this LOGARITHMIC equation.

So, IGNORE the other person's answer that x = - 2.</pre>