Question 738696
<pre>
Log base 9 of 3 to the 3x-4=x. How do I solve for x

This is easier than it "looks"!!
{{{log (9, (3^(3x - 4))) = x}}}
      {{{3^(3x - 4) = 9^x}}} ----- Converting to EXPONENTIAL form
      {{{3^(3x - 4) = (3^2)^x}}}
      {{{3^(3x - 4) = 3^(2x)}}}
        3x - 4 = 2x ----- Exponents are equated, since bases are equal
           - 4 = 2x - 3x
           - 4 = - x
         {{{highlight((- 4)/(- 1) = 4 = x)}}}</pre>