Question 1210524
. 
Let IJKLMN be a hexagon with side lengths IJ = LM = 2, JK = MN = 2, and KL = NI = 2. 
Also, all the interior angles of the hexagon are equal. Find the area of hexagon IJKLMN.
~~~~~~~~~~~~~~~~~~~~~~~~


<pre>
From the problem, all 6 sides have the same length of 2 units,
and all interior angles are equal.


So, we have a regular hexagon.


Its area is 6 times the area of the equilateral central triangle with the side length of 2 units.


So, the answer to the problem is  {{{6*a^2*(sqrt(3)/4)}}} = {{{6*2^2*sqrt(3)/4)}}} = {{{6*sqrt(3)}}} = 10.3923 square units, approximately.
</pre>

Solved.