Question 11621
<pre>
I seem to be having issues with the equations with fractions in them.  I'm getting frustrated because just when I think
I have it down, I end up with the wrong answer.  If you can please help me, here's a problem I am having issues with.
  2/3{-3/8 + [(3/4)^3 / (-3/5)^2]}
If it helps I'll say what I am doing and maybe you can tell me what I am doing wrong.  First I take 3/4^3 which is 27/64
divided by -3/5^2 which is 9/25...so at this point I have an eqation of  2/3{-3/8 + [27/64 / 9/25]} this is where
I get confused...so if you have any idea what I'm doing...please help me...thanks a million  ~V

{{{(2/3)(- 3/8 + ((3/4)^3/(- 3/5)^2))}}}
{{{(2/3)(- 3/8 + ((27/64)/(9/25)))}}} <font color = red><font size = 4><b> <==== You got up to HERE!</font></font></b>
{{{(2/3)(- 3/8 + (27/64) * (25/9))}}} ---- Applying KCF (Keep, Change, Flip) on {{{(27/64)/(9/25)}}}, to make it {{{(27/64)(25/9)}}}
{{{(2/3)(- 3/8 + (3cross(27)/64) * (25/cross(9)))}}}
{{{(2/3)(- 3/8 + (3 * 25)/64)}}}
{{{(2/3)(- 3/8 + (75)/64)}}}
{{{(2/3) ((- 3(8) + 75)/64)}}}
{{{(2/3) ((- 24 + 75)/64)}}}
{{{(2/3)(51/64)}}}
{{{(cross((2)/cross(3))(17cross(51)/32cross(64)))}}} = {{{highlight(17/32)}}}</pre>