Question 454327
The first one has a 3x, and the second one has a 5x.


Same system {{{system(15x+10y=25,15x-27y=-12)}}}


{{{system(15x=-10y+25,15x-27y=-12)}}}


Substituting for 15x in the second equation
{{{-10y+25-27y=-12}}}
{{{-37y+25=-12}}}
{{{-37y=-37}}}
{{{y=1}}}  Now use this any way you want to find x.