Question 454259
.
use substitution method to determine whether the system of linear equations has no solution, one solution, 
or many solutions
2x - y = 8
x + 4y = 13
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        The way how @mananth solves this system of equations in his post makes very bad impression.

        Normal people would solve it differently, and no one normal teacher in healthy mind would teach 

        this way as @mananth does.



<pre>
In this case, you are lucky, because you easy can express 'y' from the first equation

    y = 2x - 8

and substitute it into the second equation

    x + 4(2x-8) = 13.


Now simplify this equation and find x

    x + 8x - 32 = 13,

    x + 8x = 13 + 32

      9x   =    45

       x   =    45/9 = 5.


Now find 'y' by substituting x= 5 into  y = 2x-8 = 2*5-8 = 10-8 = 2.


<U>ANSWER</U>.  x = 5,  y = 2.
</pre>

Solved correctly, in a normal way.


Ignore the post by @mananth for the safety of your mind, since it is wrong and inappropriate teaching.