Question 236908
<pre>
I am reveiwing algebra on my own in my old age.  I am stumped on a problem. I need to find the 6th root of 225.
I have broken the equation down into the square and the 3rd root, but cannot find the book answer which is the cube
root of 15.  Can you help?  I am over half way through the book and do not move on until I have solved all of the
odd numbered problems and checked my answers against the book answers.

I don't see how the other person's answer helped at all, especially when you stated the answer, in RADICAL form,
and he/she used a calculator. Couldn't anyone with a calculator and a way to punch in the info. do that? 

Anyway, {{{highlight(root(6, 225))}}}  = {{{root(6, 15^2)}}} = {{{root(6/2, 15)}}} = {{{highlight(root(3, 15))}}}
<font color = red><font size = 4><b>OR</font></font></b>

{{{highlight(root(6, 225))}}} = {{{root(6, 15^2)}}} = {{{(15^2)^(1/6))}}} = {{{matrix(2,1, " ", 15^(2(1/6)))}}} = {{{matrix(2,1, " ", 15^(1/3))}}} = {{{highlight(root(3, 15))}}}</pre>