Question 451061
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Write an equation of the line containing the given point and parallel to the given line. 
Express your answer in the form Y=MX+b.
(-3,3);4x=5y+6
The equation of the line is Y=
(Simplify your answer. Use integers or fractions for any numbers in the expression)
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A standard consideration and treatment for this case is as follows.



<pre>
Any line parallel to the line 4x = 5y + 6 has the form 4x = 5y + c,
where 'c' is some constant.


So, the only thing we should do to solve the problem is to find
this constant 'c' from this equation. For this, we substitute the coordinates
of the given point into this equation

    4*(-3) = 5*3 + c,

    -12 = 15 + c,

    c = -12 - 15 = -27.


Thus the sought equation is

    4x = 5y - 27.


If you want it in the slope-intercept form, express 'y'

    y = {{{(4/5)x}}} + 5.4.
</pre>

That is all. At this point, the problem is solved completely.