Question 451984
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i am having troubles with solving the systems of equations in substitution. how do you solve the equation 
x-2y=0 and 4x-3y=15 in ordered pair form, (x,y)?
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        When I look at the solution by @mananth,  I see that it is done in anti-pedagogic way. 

        It is absolutely inappropriate to teach in this way.


        I will solve it in a simple manner, as simple as possible and as clear and straightforward as it should be done.



<pre>
The starting equations are

    x - 2y = 0,     (1)

    4x - 3y = 15.   (2)


From the first equation,  express  x = 2y.
Now substitute '2y' instead of 'x' into the second equation

    4(2y) - 3y = 15,

    8y - 3y = 15,

       5y   = 15,

        y   = 15/5 = 3.


Now  x = 2y = 2*3 = 6.


<U>ANSWER</U>.  x = 6, y = 3.
</pre>

Solved correctly, in a simple, clear and straightforward manner.