Question 447885
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A man goes to the bank with $6.00 and asks for change. He is given an equal number of nickels, dimes, and quarters.
How many of each is he given?
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        It is a typical  ARITHMETIC  problem for  4th  or  5th  grade students to solve it  MENTALLY  by using

        the grouping method.


        I cannot miss this opportunity to present this solution here,

        because such problems are gems for developing thinking skills in elementary school students.



<pre>
Group the coins, placing one nickel, one dime and one quarter in each group.


    +--------------------------------------------------------+
    |   According to the problem, it is possible to do so.   |
    +--------------------------------------------------------+


Then each such a group is worth  5 + 10 + 25 = 40 cents;

hence, the number of such groups is  600 cents divided by 40, which gives  {{{600/40}}} = 15
for the number of these groups.


It gives the <U>ANSWER</U>:  there are 15 coins of each nomination.
</pre>

Solved.