<PRE><B>Question 446417</B>
.
A pump can empty a swimming pool at a rate of 35 liters per minute. At that rate, how many days 
will it take to empty a pool of 10,000 gallons?
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&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;The &amp;nbsp;&quot; solution &quot; &amp;nbsp;in the post by @mananth is &amp;nbsp;INCORRECT, &amp;nbsp;since his conversion &amp;nbsp;&quot; gallons ---&gt; liters &quot; &amp;nbsp;is incorrect.


&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;The problem itself is a simple arithmetic, &amp;nbsp;and I came to bring a straightforward solution.



&lt;pre&gt;
1 gallon is 3.78541 liters.

10,000 gallons = 3.78541*10000 = 37854.1 liters.

The rate of draining is 35 liters per minute


The time of draining = {{{37854.1/35}}} = 1081.55 minutes (rounded) = 18.026 hours (rounded).


It is LESS than one day.


It is about 18 hours.
&lt;/pre&gt;

Solved, and all details are completely explained.



</PRE>