Question 434074
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Given that John's father will be twice as old as John is 11 years from now....<br>
let x = John's age 11 years from now
then 2x = father's age 11 years from now
then x-11 = John's age now
and 2x-11 = father's age now<br>
The sum of their present ages is 89:<br>
(x-11)+(2x-11) = 89
3x-22 = 89
3x = 111
x = 37<br>
John's present age = x-11 = 37-11 = 26
father's present age = 2x-11 = 74-11 = 63<br>
ANSWERS: 26 and 63<br>
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I chose to set the problem up in a different way than the other tutors.<br>
Sometimes that can make a big difference in how much work it takes to solve the problem.<br>
It didn't make much difference in this problem....<br>