Question 434087
{{{system(x=8-4y,2x-3y=13)}}}



Try this.  {{{2x=16-8y}}}, the first equation.

SUBSTITUTE into second equation.

{{{16-8y-3y=13}}}

{{{16-11y=13}}}

{{{-11y=-3}}}

{{{highlight(y=3/11)}}}


Use that value again in the original first equation.

{{{x=8-4(3/11)}}}

{{{x=88/11-12/11}}}

{{{highlight(x=76/11)}}}