Question 423336
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Any 2-part mixture problem like this can be solved using the following non-algebraic method.<br>
We are mixing 22% juice with 100% juice to obtain a mixture that is 50% juice.<br>
Consider the three percentages 22, 50, and 100 on a number line.  The difference between 22 and 50 is 28; the difference between 50 and 100 is 50.  That means the two ingredients must be mixed in the ratio 28:50; since 50% is closer to 22% than it is to 100%, the larger portion must be the original liter (1000 ml) of 22% juice.<br>
The problem is then solved using a proportion:<br>
50:28 = 1000:x
1000:560 = 1000:x<br>
ANSWER: 560 ml<br>