Question 429409
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You invested money in two funds. 
Last year, the first fund paid a dividend of 8% and the second a dividend of 5%, and you received a total of $1330. 
This year, the first fund paid a 12% dividend and the second only 2% and you received a total of $1500. 
How much money did you invest in each fund?
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        The solution in the post by @mananth is incorrect.

        I came to bring a correct solution.



<pre>
Write equations for the annual dividends for the 1st year and for the 2nd year,
as you read the problem


    0.08x + 0.05y = 1330    (1)

    0.12x + 0.02y = 1500    (2)


Multiply equation (1) by 2 (both sides).  Multiply equation (2) by 5 (both sides).  You will get

    0.16x + 0.10y = 2660     (1')

    0.60x + 0.10y = 7500     (2')


From equation (2'), subtract equation (1').  You will get

     0.44x    = 7500 - 2660

     0.44x    =     4840

         x    =     4840/0.44 = 11000.


Then from equation (1)

    y = {{{(1330 - 0.08*11000)/0.05}}} = 9000.


<U>CHECK</U>.  Equation (1), left side  0.08*11000 + 0.05*9000 = 1330  dollars.   ! correct !

        Equation (2), left side  0.12*11000 + 0.02*9000 = 1500  dollars.   ! correct !


<U>ANSWER</U>.  $11000 were invested in the first fund  and  $9000  were invested in the second fund.
</pre>

Solved correctly by the Elimination method.