Question 1210514
<br>
The problem as posted is either (1) trivial or (2) posted incorrectly.<br>
The described function is the sum of the positive integer divisors of the positive integer n.<br>
For every positive integer n greater than 1, the divisors include both 1 and n, so the sum of the integer divisors of n is at least 1+n.<br>
So (trivially) 1 is the only positive integer n for which the sum of the divisors of n is equal to 1; therefor, the number of positive integers that satisfy the given condition is 1.<br>
ANSWER: 1<br>