Question 729593
.
Given eight students four of which are females if two students are selected at random without replacement 
what is the probability that both students are females
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<pre>
The probability for the first selected student to be a female is  4/8.

Then the probability for the second selected student to be a female is  3/7.


The combined probability for two selected students (without replacement) to be females
is

    {{{(4/8)*(3/7)}}} = {{{12/56}}} = {{{3/14}}}.    <U>ANSWER</U>
</pre>

Solved.


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The answer '2/8' in the post by @lynnlo is incorrect,
so ignore his post.