Question 729988
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At a fund raising service in a church, there were twice as more women as there were men. 
The men paid $7.5 each and the women paid $5 each. The total cash collected was $3850.
How many people were in the church that day?
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        This problem ideally suits to be solved mentally.



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In accordance with the problem, we can group men and women in the church in sets,
each containing two women and one men each.


Every such group contributes 2*5 + 7.5 = 17.5 dollars into the total 3850 dollars.


Hence, the number of such groups is  3850/17.5 = 220.


It gives 220 men and 2*220 = 440 women, or 220 + 440 = 660 persons, in total.    <U>ANSWER</U>
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Solved.


You can do algebra in the same way - it will lead you to the same answer.