Question 730038
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the product of 2 consecutive odd integers is equal to 30 more than the first. Find the integers
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<pre>
Let your lesser odd number be 'n'.
Then the other odd number is (n+2).


Your equation is

    n*(n+2) = n + 30.


Simplify

    n^2 + 2n = n + 30,

    n^2 + n - 30 = 0,

    (n+6)*(n-5) = 0.


The roots are -6 and 5.


You want the odd number - so, you select 5 and reject -6.


<U>ANSWER</U>.  The numbers are 5 and 7.
</pre>

Solved.


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Ignore the answer by @lynnlo, since it is incorrect.