Question 730277
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Starting equation is

    {{{e^(x-1)}}} - 5 = 5


Add 5 to both sides

    {{{e^(x-1)}}} = 5 + 5 = 10.


Take natural logarithm of both sides

    (x-1)*ln(e) = ln(10)


Use ln(e) = 1

    x - 1 = ln(10)


<U>ANSWER</U>.  x = ln(10) + 1 = 3.302585093...


<U>CHECK</U>.  {{{e^(x-1)-5}}} = {{{2.7182818284^(3.302585093-1)-5}}} = 4.9999999996,  which is good match.
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Solved.